Route by conditional

Ionic Framework Ionic React
1

Hello

I need that depending on a variable stored in memory, when entering the site or the application, that is, when the url = “/”, it goes to one of two specific urls

The problem with the code that I have raised is that it does not show any url, everything is blank.
Why is that? It is because App should not have a return statment?

Depending if isReg equals true path="/" must route to /Registro and if isReg is false must route to /home

const App: React.FC = () => {
    
      const [isReg, setIsReg] = useState(false);
    
      useEffect(() => {
        if(getItem("isRegistered")==null){
        console.log(getItem("isRegistered"));
        setIsReg(true);
      }
      else{
        setIsReg(false);
      }
    }, []);
    
      if(isReg){
        return (
          <IonApp>
            <IonReactRouter>
            <IonSplitPane contentId="main" when="(min-width: 4096px)">
                  <Menu />
              <IonRouterOutlet id="main">
              <Route path="/" component= {Registro } exact={true}/>
    
              </IonRouterOutlet>
              </IonSplitPane>
            </IonReactRouter>
          </IonApp>
          );
      }
      else{
        return (
          <IonApp>
            <IonReactRouter>
            <IonSplitPane contentId="main" when="(min-width: 4096px)">
                  <Menu />
              <IonRouterOutlet id="main">
                <Route path="/" component= {Home} exact={true}/>
    
              </IonRouterOutlet>
              </IonSplitPane>
            </IonReactRouter>
          </IonApp>
          );
      }
      
    };

Thanks in advance.