I have a gulpfile.js with a default function and which accepts a argument. (for eg. gulp --country IN).
Gulp function takes that parameter name, copies some folders and files of the passed argument deletes them, modify json data and move it into some other folder. So basically, I used 3 gulp tasks (gulp-param, gulp-clean, gulp-json-modify).
And then after that I run ionic serve. I want to know if I can run ionic serve with a paramter or write a new command that runs the gulp code first (we can replace it with ionic app scripts) and then runs the ionic serve command.
In short, I want to run one command instead of 2 but still solves the purpose