I’m facing gulp 4 issue Task function must be specified
Node version: 12.9.1
NPM: 6.10.3
(unfortunately, I cannot degrade node)
My gulpfile.js
var gulp = require('gulp');
var sass = require('gulp-sass');
var cleanCss = require('gulp-clean-css');
var rename = require('gulp-rename');
var paths = {
sass: ['./scss/**/*.scss']
};
gulp.task('default', ['sass']);
gulp.task('sass', function(done) {
gulp.src('./scss/ionic.app.scss')
.pipe(sass())
.on('error', sass.logError)
.pipe(gulp.dest('./www/css/'))
.pipe(cleanCss({
keepSpecialComments: 0
}))
.pipe(rename({ extname: '.min.css' }))
.pipe(gulp.dest('./www/css/'))
.on('end', done);
});
gulp.task('watch', ['sass'], function() {
gulp.watch(paths.sass, ['sass']);
});
my package.json
...
"gulp": "^4.0.2",
"gulp-clean-css": "^4.2.0",
"gulp-rename": "^1.4.0",
"gulp-sass": "^4.0.2",
...
Does anyone has updated gulp.js for ionic 1 & node 12+ ?
(Meanwhile, I’m looking into the migration of gulpfile.js to v4 syntax)