Admob Free plugin_not_installed

I have a basic set up for admob free in Ionic 3 and I can get it to show with isTesting set to true. However when I put an id into bannerConfig it fails and I get an error of plugin_not_installed.

constructor(public navCtrl: NavController, private admobFree: AdMobFree) {

this.showBannerAd();

}

showBannerAd() {

  const bannerConfig: AdMobFreeBannerConfig = {
    id: 'ca-app-pub-5742208320359495/3836512351',
    // isTesting: true,
    autoShow: true
  }

  this.admobFree.banner.config(bannerConfig);

  this.admobFree.banner.prepare()
    .then((result) => {
      // this.admobFree.banner.show()
      // banner Ad is ready
      // if we set autoShow to false, then we will need to call the show method here
    })
    .catch(e => alert(e + ' ' + bannerConfig.id));

cli packages: (/usr/local/lib/node_modules)

@ionic/cli-utils  : 1.19.0
ionic (Ionic CLI) : 3.19.0

global packages:

cordova (Cordova CLI) : 7.1.0

local packages:

@ionic/app-scripts : 3.1.5
Cordova Platforms  : ios 4.5.4
Ionic Framework    : ionic-angular 3.9.2

System:

ios-deploy : 1.9.2
Node       : v6.11.1
npm        : 5.6.0
OS         : macOS High Sierra
Xcode      : Xcode 9.2 Build version 9C40b

Environment Variables:

ANDROID_HOME : not set

Misc:

backend : pro

Hi,

I have the same issue here, did you find something ?

Ionic info :
cli packages:

@ionic/cli-utils  : 1.19.1
ionic (Ionic CLI) : 3.19.1

global packages:

cordova (Cordova CLI) : 7.1.0

local packages:

@ionic/app-scripts : 3.1.8
Cordova Platforms  : android 6.3.0
Ionic Framework    : ionic-angular 3.9.2

System:

Android SDK Tools : 26.1.1
Node              : v8.5.0
npm               : 5.6.0
OS                : Windows 10

Environment Variables:

ANDROID_HOME : C:\Users\YaYap\AppData\Local\Android\Sdk

Misc:

backend : pro 

Best regards,
Vianney

please check your plugin list.

I uninstalled and then reinstalled my plugins and platforms.

Then I used https://blog.paulhalliday.io/2017/06/24/ionic-3-admobfree/ as my example for code and it worked perfectly.